Question

$( {10}^{2} - {8}^{2} ) \div 6 \div 2 + {1}^{2019}$
va rog repedeeee!!!​

Answer 1

Răspuns:

buna !

$(10 {}^{2} - 8 {}^{2} ) \div 6 \div 2 + 1 {}^{2019}$

$(100 - 2 {}^{6} ) \div 6 \div 2 + 1$

$(100 - 64) \div 6 \div 2 + 1$

$36 \div 6 \div 2 + 1$

$3 + 1$

$4$