Question

$2\frac{1}{2} - ( + \frac{5}{4} ) - 1.(5)$
„.”=>virgula

(5)=>perioada

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$\frac{5}{3} - ( - \frac{2}{3} ) + \frac{1}{6}$
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Answer 1

$2 \frac{1}{2} - ( + \frac{5}{4} ) - 1.(5) \\ \frac{5}{2} - \frac{5}{4} - \frac{15 - 1}{9} = \frac{5}{2} - \frac{5}{4} - \frac{14}{9} \\ 2.500 - 1.250 - 1.555 = 1.250 - 1.555 = - 0.30(5) \\ \\ \\ \frac{5}{3} - ( - \frac{2}{3} ) + \frac{1}{6} = \frac{2 \times 5 + 2 \times 2 + 1}{6} = \frac{10 + 4 + 1}{6} \\ \frac{15}{6} = 2.5$