Question

$(2- \frac{4}{3} )^{2} : \frac{2}{9} =?$ dau coroana

Answer 1

$\displaystyle \left(2- \frac{4}{3} \right)^2: \frac{2}{9} =\left( \frac{6}{3} - \frac{4}{3} \right)^2: \frac{2}{9} =\left( \frac{2}{3} \right)^2: \frac{2}{9} = \frac{2^2}{3^2} : \frac{2}{9} = \frac{\not4_2}{\not9_1} \cdot \frac{\not9_1}{\not2_1} =2$