Question

$2 \sqrt{24}( \frac{3}{ \sqrt{6}} - \frac{ \sqrt{2} }{ \sqrt{3} } )$

Answer 1

4√6($\frac{3- \sqrt{2} \sqrt{2} }{ \sqrt{6} }$)=4√6($\frac{1}{ \sqrt{6} }$)=$\frac{4 \sqrt{6} }{ \sqrt{6} }=4$