Question

$2 \sqrt{32} - 6 \div \sqrt{18} =$
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Answer 1

$2 \sqrt[]{32} - 6 \div \sqrt{18} =$

${2}^{3} \sqrt{2} - 6 \div \sqrt{18 = }$

${2}^{3} \sqrt{2} - \frac{6}{ \sqrt{18} } =$

$8 \sqrt{2} - \frac{6}{ \sqrt{18} } =$

$8 \sqrt{2} - \frac{6}{3 \sqrt{2} } =$

$8 \sqrt{2} - \frac{2}{ \sqrt{2} } =$

$8 \sqrt{2} - \sqrt{2} =$

$7 \sqrt{2}$