Question

$2/ \sqrt2- \sqrt6/ \sqrt3 =?$

Answer 1

$\rm \frac{2}{\sqrt2} - \frac{\sqrt^2\not6}{\sqrt\not3}= \frac{2}{\sqrt2}- ^{\sqrt2}\sqrt2= \frac{2}{\sqrt2} - \frac{2}{\sqrt2}=\boxed{\bold{0}}$