Question

[tex]-2 x^{2} +5x+3m+13=0
[/tex]
2apartineS m-? de aflat ))
a doua Determinati nr real m pentru care ecuatia urmatoare are o singura solutie
$5 x^{2} -7x+m=0$
$x^{2} +4x+m-1=0$

Answer 1

-2x²+5x+3m+13=0
inlocuim  x=2
-2×2²+5×2+3m+13=0
-8+10+3m+13
3m=-15
m=-15/3
m=-5

5x²-7x+m=0
a=5
b=-7
c=m
Δ=(-7)²-4×5×m =49-20m
ca sa aiba o solutie Δ =0  deci  49-20m=0  ⇒m=49/20


x²+4x+m-1=0
a=1
b=4
c=m-1
Δ=4²-4(m-1) =16-4m+4=20-4m
ca sa aiba o solutie Δ =0  deci  20-4m=0  ⇒m=5