Question

$3^{1-log inbaza3din 10} -4 ^{1-login baza 4 din 5} + 6 ^{log in baza 6 din 9 -1}$
cum se poate scrie sub o forma mai simpla ?
Ma multumesc cu o idee!

Answer 1

Asa, ca inainte de a pleca la facultate:

$\frac{3^1}{3^{log_310}} - \frac{4^1}{4^{log_45}}-\frac{6^{log_69}}{6^1} = \frac{3}{10^{log_33}} - \frac{4}{5^{log_44}} - \frac{9^{log_66}}{6} = \frac{3}{10} - \frac{4}{5} - \frac{9}{6}$

Succes.