Question

$(({3 {}^{4} }^{} - {2}^{3} \times 10) \div {6}^{0} + {5}^{12} \div {25}^{6} \times 5) \times {2}^{3}$
va rog dau coroană
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Answer 1

$((3^4-2^3\times10)\div6^0+5^{12}\div25^6\times5)\times2^3=\\ \\((3^4-2^3\times10)\div1+5^{12}\div\left(5^2\right)^6\times5)\times2^3=\\ \\(3^4-2^3\times10+5^{12}\div5^{2\times6}\times5)\times2^3=\\ \\(3^4-8\times10+5^{12}\div5^{12}\times5)\times2^3=\\\\(81-80+5)\times2^3=\\\\6\times8=48$