Question

$(3 \sqrt{2} \times 4 \sqrt{3} \div - 12 \sqrt{6} ) {}^{ - 2019}$
Ajutorrrrrrrrrrrrrrrr​

Answer 1

$(3 \sqrt{2} \times 4 \sqrt{3} \div - 12 \sqrt{6} )^{ - 2019} = (12 \sqrt{6} \div - 12 \sqrt{6} )^{ - 2019} = ( - 1)^{ - 2019} = - 1$

Answer 2

Răspuns:

-1

Explicație pas cu pas:

=[12√6 : (-12√6)] ⁻²⁰¹⁹ =

[12√6 × (-1/12√6)] ⁻²⁰¹⁹ =

(-1)⁻²⁰¹⁹=               (-1 la putere impara =-1)

1/(-1)=

-1