Question

$3 \sqrt2{x} +7=0$

Answer 1

$3\sqrt2\cdot x+7=0 \\ 3\sqrt2\cdot x=-7 \\ x= \frac{-7}{3\sqrt2}= \frac{-7\sqrt2}{6}$

Answer 2

$\displaystyle 3 \sqrt{2} x+7=0 \\ 3 \sqrt{2} x=0-7 \\ 3 \sqrt{2} x=-7 \\ x=- \frac{7}{3 \sqrt{2} } \\ \\ x=- \frac{7 \sqrt{2} }{3 \cdot 2} \\ \\ x=-\frac{7 \sqrt{2} }{6}$