Question

$(3 \times {4}^{2} - {3}^{4} ) {}^{2} \times \frac{2}{63} + \frac{ {5}^{3} - {5}^{2} } { {4}^{2} - 4}$
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Answer 1

${(3 \times {4}^{2} - {3}^{4} )}^{2} \times \frac{2}{63} + \frac{ {5}^{3} - {5}^{2} }{ {4}^{2} - 4 } = {(3 \times 16 - 81)}^{2} \times \frac{2}{ {3}^{2} \times 7 } + \frac{ {5}^{2} (5 - 1)}{4(4 - 1)} = { (48 - 81) }^{2} \times \frac{2}{ {3}^{2} \times 7 } + \frac{25}{3} = {( - 33)}^{2} \times \frac{2}{ {3}^{2} \times 7} + \frac{25}{3} \\ = {3}^{2} \times {11}^{2} \times \frac{2}{ {3}^{2} \times 7} + \frac{25}{3} = \frac{2 \times 121}{7} + \frac{25}{3} = \frac{242}{7} + \frac{25}{3} = \frac{242 \times 3 + 25 \times 7}{21} = \frac{726 + 175}{21} \\ = \frac{901}{21}$