Question

$4 - x^{2}= \frac{x+8}{3}$

Answer 1

4-x^2=x+8 / 3
3×(4-x^2)=x+8
12-3x^2=x+8
-3x^2-x=8-12
-3x^2-x+4=0
delta=b^2-4ac=1+48=49
x1=(1+√49)/-6=(1+7)/-6=(-8/6)=(-4/3)
x2=(1-√49)/-6=(1-7)/-6=(-6)/-6=1