Question

$5 {}^{140} \div 25 {}^{70} + 8 { {}^{32} }^{} \div 16 {}^{24} + 100 {}^{26} \div 10 {}^{48} - 2 {}^{5} \times 5 {}^{2}$
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Answer 1

Răspuns:

$5 {}^{140} \div 25 {}^{70} + {8}^{32} \div 16 {}^{24} + 100 {}^{26} =$

$5 {}^{140} \div 5 {}^{140} + 2 {}^{ 96} \div 2 {}^{96} + 100 {}^{26} =$

$1 + 1 + 100 {}^{26} =$

$2 + 100 {}^{26}$

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