Question

$5(x + 2) + 8 \leqslant 3(4x - 9)$
si x<10​

Answer 1

Răspuns:

5(x+2)+8≤3(4x-9), x<10

5x+10+8≤12x-27

5x+18≤12x-27

45≤7x

x≥$\frac{45}{7}$

x∈[$\frac{45}{7}$,10)

Answer 2

Răspuns:

Explicație pas cu pas:

5(x+2)+8≤3(4x-9)      5x+10+8≤12x-27       -7x≤-27-18   7x≥45    x≥6,4285

x<10        ⇒x∈[6,4285, 10)