Question

$7 {}^{2003} + 8 {}^{2007} + 9 {}^{2011}$
Dau coroana plzz.
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Answer 1

Răspuns:

uc(7²⁰⁰³+8²⁰⁰⁷+9²⁰¹¹ ) = 4

Explicație pas cu pas:

uc(7²⁰⁰³+8²⁰⁰⁷+9²⁰¹¹ )= ?

uc(7¹) = 7 ; uc(7²) = 9 ; uc(7³) = 3 ; uc(7⁴) = 1

2003 = 500x4 + 3 => uc(7²⁰⁰³) = uc(7³) = 3

uc(8¹) = 8 ; uc(8²) = 4 ; uc(8³) = 2 ; uc(8⁴) = 6

2007 = 501x4 +3 => uc(8²⁰⁰⁷) = uc(8³) = 2

uc(9¹) = 9 ; uc(9²) = 1

2011 = 1005x2+1 => uc(9²⁰¹¹) = uc(9¹) =9

uc(7²⁰⁰³+8²⁰⁰⁷+9²⁰¹¹ ) = uc(3+2+9) = 4

uc(7²⁰⁰³+8²⁰⁰⁷+9²⁰¹¹ ) = 4