Question

$7 \sqrt5 + 2 \sqrt{5}$
$13 \sqrt{7} - 6 \sqrt{7} + 7 =$
$2 \sqrt{5} \times 3 \sqrt{10} =$
$\frac{1}{ \sqrt{12 } } =$
ma ajutati va rog si.imi explicați si mie cum se face?​

Answer 1

Răspuns:

Explicație pas cu pas:

$7\sqrt{5}+2\sqrt{5}=(7+2)*\sqrt{5}=9\sqrt{5}\\ 13\sqrt{7}-6\sqrt{7} +7 = (13-6)*\sqrt{7} +7=7\sqrt{7} +7=7*(\sqrt{7}+1)\\ 2\sqrt{5} *3\sqrt{10}=2*3*\sqrt{5*10} =6\sqrt{50} =6\sqrt{25*2} =6*\sqrt{25}*\sqrt{2}=6*5\sqrt{2} =30\sqrt{2} \\\frac{1}{\sqrt{12} }=\frac{1}{\sqrt{4*3} }=\frac{1}{2\sqrt{3} }=\frac{1*\sqrt{3}}{2\sqrt{3} *\sqrt{3} }=\frac{\sqrt{3} }{2*(\sqrt{3})^{2} }=\frac{\sqrt{3} }{2*3} =\frac{\sqrt{3} }{6}$

Answer 2

7rad5 + 2rad5 = 9rad5

13rad7 - 6rad7 + 7 =

= 7rad7 + 7

= 7(rad7 + 1)

2rad5 × 3rad10 =

= 6rad50

= 6×5rad2

= 30rad5

1/rad12 = rad12/12 = 2rad3/12 = rad3/6