Question

$8 {}^{x} = 4 {}^{2x \ + 1}$

Answer 1

Mult succes în continuare!

Answer 2

$8^{x}=4^{2x+1}\\ \\ (2^{3})^{x}=(2^{2})^{2x+1}\\ \\ 2^{3x}=2^{2(2x+1)}\\ \\ 2^{3x}=2^{4x+2}\\ \\ \Rightarrow 3x=4x+2\\ \\ -2=4x-3x\\ \\ \boxed{x=-2},~S=\{-2\}$