Question

$81^{ \frac{1}{4}- \frac{1}{2} log_{9}4 }*49 ^{ log_{7}2 } =$

Answer 1

$\frac{ 81^{ \frac{1}{4} } }{81^{ \frac{1}{2} *log _{9}4 }}*7^{2*log_7 2} = \frac{3^ \frac{4}{4} }{9^{log_94}}*7^{log_74}= \frac{3}{4}*4=3$