Question

$9^{17} : 27^{10}= ?$

Answer 1

$9^{17}: 27^{10} =\boxed{81}$

$9^{17}$=
=$( 3^{2})^{17}$
=$3^{34}$
$27^{10}$=
⇒$(3^{3})^{10}$
⇒$3^{30}$

$3^{34}- 3^{30}= 3^{4} \\ 3^{4}=\boxed{81}$

Answer 2

9^17=(3^2)^17=3^34
27^10=(3^3)^10=3^30
bazele sunt egale exponentii se scad adica
34-30=4
3^4=81