Question

$(a-b)^{2}$+$(a+\sqrt{3}) ^{2}$ calculați a si b

Answer 1

$(a-b)^{2} +(a+\sqrt{3} )^2=\\a^{2} -2ab+b^{2} +a^{2} +2\sqrt{3} a+3=\\2a^2-2ab+2\sqrt{3} a+b^2+3=\\=2a^2-2a(b+\sqrt{3} )+b^2+3$

nefiind egalat cu ceva...cred ca atat e rezultatul .

Answer 2

$\it (a-b)^2+(a+\sqrt3)^2=0 \Rightarrow \begin{cases}\it (a-b)^2=0 \Rightarrow a-b=0 \Rightarrow a=b\ \ \ \ \ (1)\\ \\ \it (a+\sqrt3)^2=0 \Rightarrow a+\sqrt3=0 \Rightarrow a=-\sqrt3 \ \ \ (2)\end{cases}\\ \\ \\ (1),\ (2) \Rightarrow a=b=-\sqrt3$