Question

$f\::\:R\:\rightarrow \:R,\:\:f\:\left(x\right)=x\sqrt{2}+3\:si\:g\::\:R\:\rightarrow \:\:R,\:g\left(x\right)=3x+\sqrt{2}$
Rezolvati in multimea numerelor reale ecuatia $f\left(x\right)=g\left(x\right)$

Answer 1

x√2+3=3x+√2
x√2-3x=√2-3
x(√2-3)=√2-3
x=√2-3/√2-3
x=1