Question

$\fbox{AM 96} Sa se determine multimea tuturor numerelor reale x care \\ verifica inegalitatea: \\ \\ e^x-1-x- \frac{x^2}{2!}- \frac{x^3}{3!} - \frac{x^4}{4!} \geq 0 \\ \\ a) (0, \infty) \quad\quad \quad \ b) (-\infty, 0) \quad\quad\quad \ c) [0, \infty) \quad\quad\quad d) \mathbb_{R}\quad\quad\quad f) \emptyset$

Cum se rezolva? Ajutati-ma va rog.

Answer 1

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