Question

$\frac{1}{10 \times 11} + \frac{1}{11 \times 12} ... + \frac{1}{99 \times 100} > 0.08$
e urgentt

Answer 1

$\frac{1}{10} - \frac{1}{11} + \frac{1}{11} - \frac{1}{12} + ... + \frac{1}{99} - \frac{1}{100} = \frac{1}{10} - \frac{1}{100} = 0.1 - 0.01 = 0.09 > 0.08$