Question

$\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{7}{12} + \frac{3}{4} + \frac{3}{12}$
Ma ajutati va roog mult chiar nu stiu!! ~_~

Answer 1

${ \frac{1}{2} }^{6} + { \frac{1}{3} }^{4} + { \frac{1}{4} }^{3} + \frac{7}{12} + { \frac{3}{4} }^{3} + \frac{3}{12} = \frac{6}{12} + \frac{4}{12} + \frac{3}{12} + \frac{10}{12} + \frac{9}{12} = \frac{32}{12} = \frac{8}{3}$
in poza este rezolvarea

Answer 2

$\frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{7}{12} + \frac{3}{4} + \frac{1}{4} = \\ \frac{6 + 4 + 3 + 7+4+ 3}{12} = \\ \frac{27}{12}= \frac{9}{4}$