Question

$( \frac{1}{2} - \frac{3}{4} ) {}^{3} \div ( - \frac{1}{4} ) {}^{2} - 0.5 = \frac{ \times }{16}$
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Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Răspuns:

-12

Explicație pas cu pas:

${\Big( \frac{1}{2} - \frac{3}{4} \Big)}^{3} \div {\Big( - \frac{1}{4} \Big)}^{2} - 0.5 = \frac{x}{16} \\ {\Big( \frac{^{2)} 1}{2} - \frac{3}{4} \Big)}^{3} \div \frac{1}{ {4}^{2} } - \frac{1}{2} = \frac{x}{16} \\{\Big(\frac{2 - 3}{4} \Big)}^{3} \cdot {4}^{2} - \frac{1}{2} = \frac{x}{16} \\ {\Big( - \frac{1}{4} \Big)}^{3} \cdot {4}^{2} - \frac{1}{2} = \frac{x}{16} \\ - \frac{1}{ {4}^{3} } \cdot {4}^{2} - \frac{1}{2} = \frac{x}{16} \iff - \frac{1}{4} - \frac{^{2)} 1}{2} = \frac{x}{16} \\ - \frac{1 + 2}{4} = \frac{x}{16} \iff - \frac{3}{4} = \frac{x}{16} \\ x = - \frac{3 \cdot 16}{4} \implies \bf x = - 12$