Question

$\frac{1}{3}< \frac{2}{x-1} \leq \frac{8}{3}$.Va rog este URGENT!!

Answer 1

[tex] \frac{1}{3}^{(8}<\frac{2}{x-1}^{(4} \leq \frac{8}{3} \\ \frac{8}{24}< \frac{8}{4x-4} \leq \frac{8}{3} \\ 24>4x-4 \geq 3|+4 \\ 28>4x \geq 7|:4 \\ 7>x \geq 1 \Longrightarrow \boxed{x \in [1,7) }[/tex]