Question

$(\frac{1}{ \sqrt{8} } )^x \geq \frac{1}{2}$

Answer 1

a^x=b⇒loga(b)=x
log1/√8 din (1/2)≥x⇔log√8^(-1) din (1/2)≥x⇔log8(-1/2)din 2^(-1)≥x⇔
2log8din2≥x⇔2log2^3din2≥x⇔2/3log2din2≥x⇔(2/3)·1≥x⇔x≤2/3