Question

$\frac{18 x^{2} -3x-10}{9 x^{2} +12x+4}$
URGENT!!!! Dau coroana!!!

Answer 1

18x²-3x-10
Δ= (-3)²-4*18*(-10) = 9+720 =729
x1 = (3-√729)/2*18 = (3-27)/36 = -24/36=-2/3
x2=(3+27)/2*18 = 30/36 =5/6
=> 18x²-3x-10= (x+2/3)*(x-5/6)
9x²+12x+4
Δ= 12²-4*9*4 = 144-144=0
x1=x2=-12/2*9 = -2/3
=> 9x²+12x+4= (x+2/3)²
=>  =  (x+2/3)*(x-5/6)/(x+2/3)² = (x-5/6)/(x+2/3)=6x-5/6 * 3/(3x+2) = (6x-5)/(6x+4)