Question

$\ \frac{2}{3} (4x- \frac{1}{3} )= \frac{1}{9}$

Answer 1

[tex]\frac{2}{3}(^{3)}4x-\frac{1}{3})= \frac{1}{9} \\ \frac{2}{3}( \frac{12x}{3}- \frac{1}{3})= \frac{1}{9} \\ \frac{2}{3}* \frac{12x-1}{3}= \frac{1}{9} \\ \frac{24x-2}{9}= \frac{1}{9} \\ 24x-2=1 \\ 24x=3 \\ \boxed{x= \frac{1}{8}} [/tex]