Question

$\frac{2}{3}[ \frac{3(3x+14)}{4}- \frac{1}{4} ( \frac{2x+3}{4}- \frac{3x-2}{5})]= \frac{1}{3}[ \frac{3(5x+19)}{2}- \frac{3}{2}( \frac{2x-3}{5}+ \frac{13-x}{2})-3x]$

Answer 1

6(3x+14)/12-3/12[(2x+3)/4-(3x-2)/5]=3(5x+19)/6-3/6[(2x-3)/5+(13-x)/2]-3x/3
(3x+14)/2-(2x+3)/16+(3x-2)/20=(5x+19)/2-(2x-3)/10-(13-x)/4-x
aducem la acelasi numitor
[40(3x+14)-5(2x+3)+4(3x-2)]/80=[40(5x+19)-8(2x-3)-20(13-x)-80x]/80
120x+560-10x-15+12x-8=200x+760-16x+24-260+20x-80x
122x+537=124x+524
122x-124x=524-537
-2x=-13    inmultim -1
x=13/2
x=6,5