Question

[tex] (\frac{3}{2} ) ^{-1} =?
[/tex]$(\frac{1}{4} ) ^{-2}$ vreau si explicatie plizz

Answer 1

$\left(\dfrac32\right)^{-1}=\dfrac{1}{\dfrac32}=1\cdot\dfrac23=\dfrac23$
Pentru al doilea am mai dat o rezolvare, asa ca acum dau alta:

$\left(\dfrac14\right)^{-2}=\dfrac{1^{-2}}{4^{-2}}=\dfrac{1}{\dfrac{1}{4^2}}=1\cdot\dfrac{4^2}{1}=16$