Matematică, întrebare adresată de vladandrei2008, 8 ani în urmă


 + ( \frac{3}{5}  \div 6 +  \frac{1}{2}  \div  \frac{5}{6} ) \div ( \frac{3}{8}  + 1) \div ( \frac{11}{10}  - 1) =


tcostel: Ce-i cu plusul ala in fata primei paranteze?
vladandrei2008: fără plus

Răspunsuri la întrebare

Răspuns de tcostel
0

\displaystyle\bf\\ \left(\frac{3}{5}:6+\frac{1}{2}:\frac{5}{6}\right):\left(\frac{3}{8}+1\right):\left(\frac{11}{10}-1\right)=\\\\\\=\left(\frac{3}{5\times6}+\frac{1}{2}\times\frac{6}{5}\right):\left(\frac{3+1\times8}{8}\right):\left(\frac{11-1\times10}{10}\right)=\\\\\\=\left(\frac{3}{30}+\frac{6}{10}\right):\left(\frac{11}{8}\right):\left(\frac{1}{10}\right)=\\\\\\=\left(\frac{1}{10}+\frac{6}{10}\right):\left(\frac{11}{8}\right):\left(\frac{1}{10}\right)=

.

\displaystyle\bf\\=\frac{7}{10}:\frac{11}{8}:\frac{1}{10}=\\\\\\=\frac{7}{10}\times\frac{8}{11}:\frac{1}{10}=\\\\\\=\frac{56}{110}:\frac{1}{10}=\\\\\\=\frac{56}{110}\times\frac{10}{1}=\\\\\\=\frac{56\times10}{110}=\boxed{\bf\frac{56}{11}}

 

 

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