Question

[tex] \frac{3x-2}{2}- \frac{4x-1}{3} + \frac{2x-3}{4} =1- \frac{x-1}{6}
[/tex]

Answer 1

(3x-2)/2-(4x-1)/3+(2x-3)/4=1-(x-1)/6
se aduce la acelasi numitor comun, 24 si vom amplifica prima data cu 12, apoi cu 8, cu 6 si in membrul drept cu 24 si ultima cu 4
Va rezulta:

12(3x-2)-8(4x-1)+6(2x-3)=24-4(x-1)

36x-24-32x+8+12x-18=24-4x+4

4x+12x+4x=28+24-10

20x=62

x=31/10

Answer 2

Aducem la acelasi numitor  (12)

$\frac{6(3x-2)}{12} - \frac{4(4x-1)}{12} + \frac{3(2x-3)}{12} = \frac{12}{12} - \frac{2(x-1)}{6}$

Putem inmulti acuatia cu 12 ca sa scapam de numitor 

$6(3x-2)-4(4x-1)+3(2x-3)=12-2(x-1)$

$18x-12-16x+4+6x-9=12-2x+2$

$8x-17=14-2x$

$8x+2x=14+17$

$10x=31 =\ \textgreater \ x= \frac{31}{10}$