Question

$( \frac{4}{radical din 50} + \frac{3}{radical din 18} - \frac{1}{radical din 32} )$ × $\sqrt{2}$

Dau coronita!!!!

Answer 1

(4/5√2+3/3√2-1/4√2)x√2=
=4/5+1-1/4=
=(16+20-5)/20=
=31/20

O seara buna!

Answer 2

$( \frac{4}{ \sqrt{50} } + \frac{3}{ \sqrt{18} } - \frac{1}{ \sqrt{32} })* \sqrt{2} = \\ \frac{4}{ \sqrt{50} }*\sqrt{2}+\frac{3}{ \sqrt{18} }*\sqrt{2}-\frac{1}{ \sqrt{32} }*\sqrt{2}= \\ \frac{4}{5} +1- \frac{1}{4}= \frac{16+20-5}{20} = \frac{31}{20}$

/robèrtinni