Question

$( \frac{6}{3 \sqrt \sqr{2}-2 \sqrt{3} } ) ^{2}$

Answer 1

$(\frac{6}{3 \sqrt{2}-2 \sqrt{3} })^2=( \frac{6(3 \sqrt{2}+2 \sqrt{3} ) }{(3 \sqrt{2}-2 \sqrt{3})( 3 \sqrt{2}+2 \sqrt{3}) })^2= (\frac{6(3 \sqrt{2}+2 \sqrt{3}) }{18-12})^2 = \\ =(3 \sqrt{2}+2 \sqrt{3})^2=18+12+12 \sqrt{6}=30+12 \sqrt{6}$