Question

[tex] \frac{7}{36}-\frac{1}{72}-\frac{5}{24} :\frac{6}{9}+\frac{75}{99} .\frac{5}{9}+\frac{3}{4} 

Answer 1

$\displaystyle \frac{7}{36}-\frac{1}{72}-\frac{5}{24} :\frac{6}{9}+\frac{75}{99} \cdot \frac{5}{9}+\frac{3}{4}= \\ \\ = \frac{7}{36} - \frac{1}{72} - \frac{5}{24} \cdot \frac{9}{6} + \frac{375}{891} + \frac{3}{4} = \\ \\ = \frac{7}{36} - \frac{1}{72} - \frac{45}{144}+ \frac{375}{891} + \frac{3}{4} = \\ \\ = \frac{2772-198-4455+6000+10692}{14256} = \frac{14811}{14256} ^{(3}= \frac{4937}{4752}$