Question

$\frac{9 \sqrt{6} x + 3x}{9} = 9$
x=? va rog
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Answer 1

$\frac{9\sqrt{6} x+3x}{9} =9$

$\frac{3(3\sqrt{6}x+x) }{9}=9$

$\frac{3\sqrt{6} x+x}{3} =9 |*3$

$3\sqrt{6} x+x=3*9$

$3\sqrt{6} x+x=27$

$x(3\sqrt{6} -1)=27$

$x=\frac{27}{3\sqrt{6}+1 }$

$x=\frac{27(3\sqrt{6}-1) }{(3\sqrt{6}+1)(3\sqrt{6}-1) }$

$x=\frac{27(3\sqrt{6} -1)}{3*3*6-1}$

$x=\frac{27*3\sqrt{6}-27 }{54-1}$

$x=\frac{81\sqrt{6}-27 }{53}$