Question

$\frac{ \sqrt{13+ \sqrt{1296} }}{x} =\frac{ 3^{3} - 3^{2} - 3 - 3^{0}} { \sqrt{23+ \sqrt{1618} } }$

URGENT !!!! AJUTOR !!!!!!!!!!!!!

Answer 1

$\displaystyle \frac{ \sqrt{13+ \sqrt{1296} } }{x} = \frac{3^3-3^2-3-3^0}{ \sqrt{23+ \sqrt{1618} } } \\ \\ \frac{ \sqrt{13+36} }{x} = \frac{27-9-3-1}{ \sqrt{23+ \sqrt{1618} } } \\ \\ \frac{ \sqrt{49} }{x}= \frac{14}{ \sqrt{23+ \sqrt{1618} } } \\ \\ \frac{7}{x} = \frac{14}{ \sqrt{23+ \sqrt{1618} } } \\ \\ 14x=7\left( \sqrt{23+ \sqrt{1618} } \right) \\ \\ x= \frac{7\left( \sqrt{23+ \sqrt{1618} } \right) }{14} \\ \\ x= \frac{ \sqrt{23+ \sqrt{1618} } }{2}$