Question

$\frac{ \sqrt{63} + \sqrt{28} }{ \sqrt{7} }$ rezolvare completa va rog rezultatul este 5

Answer 1

[tex] \frac{3\sqrt{7}+2\sqrt{7}}{\sqrt{7}} = \frac{5\sqrt{7}}{\sqrt{7}} =5\\ Obs. \sqrt{63} =\sqrt{9*7}= \sqrt{9} * \sqrt{7} =3\sqrt{7}\\ \sqrt{28} =\sqrt{4*7}= \sqrt{4} * \sqrt{7} =2\sqrt{7}[/tex]