Question

$\frac{ \sqrt{8}+2 }{ \sqrt{8}-2 } = \frac{ \sqrt{2}+1 }{ \sqrt{2} -1}$

Answer 1

$\frac{ \sqrt{8}+2 }{ \sqrt{8}-2}= \frac{2 \sqrt{2}+2 }{2 \sqrt{2}-2 }= \frac{2( \sqrt{2}+1 )}{2( \sqrt{2}-1 )}= \frac{ \sqrt{2}+1 }{ \sqrt{2}-1 }$