Question

$\frac{ x^{2} -49}{ x^{2} -7x}- \frac{2x+7}{ x^{2}+x}: \frac{1}{x+1}$
E(x)= -1

Answer 1

$\frac{(x-7)(x+7)}{x(x-7)} - \frac{2x+7}{x(x+1)} *(x+1)$ =

$\frac{x+7}{x} - \frac{2x+7}{x}$ =

$\frac{x+7-2x+7}{x}$ =

$\frac{-x}{x}$ =-1