Question

$\frac{x}{ x^{2} -9} + \frac{2}{x+3} + \frac{1}{3-x}$ cum aduc la acelasi numitor ?

Answer 1

$\frac{x}{ x^{2} -9} + \frac{2}{x+3} + \frac{1}{3-x} = \frac{x}{ (x-3)(x+3)}+\frac{2}{x+3} - \frac{1}{x-3} = \\ \frac{x+2(x-3)-(x+3)}{(x-3)(x+3)} = \frac{2x-9}{(x-3)(x+3)}$