Question

$\int\limits^0_1 {x e^{2x} } \, dx =$

Answer 1

I=$\int\limits^0_1 {x e^{2x} } \, dx = \frac{1}{2} \int\limits^0_1 {2x e^{2x} } \, dx =- \int\limits^1_0( { e^{2x})' } \, dx =$$e^{2x}$ dela 0 la 1= e^1-e^0= e-1