Question

$\left \{ {{x+y=13} \atop {8x+10y=120}} \right.$
$\left \{ {{x-y=2} \atop {4x-5y=0}} \right.$
$\left \{ {{x-y=4} \atop {-3x+2y= -2}} \right.$
Rezovlare sisteme
Ajutati'ma :*

Answer 1

x+y=13
8x+10y=120

x=13-y
8(13-y)+10y=120
104-8y+10y=120
2y=16
y=8
x=13-8=5

x-y=2
4x-5y=0

x=2+y
4(2+y)-5y=0
8+4y-5y=0
y=8
x=8+2=10

x-y=4
-3x+2y=-2

x=4+y
-3(4+y)+2y=-2
-12-3y+2y=-2
y=-10
x=-6