Question

$log_{3}(x+2)-log_{3}(x-4)=1$

Answer 1

[tex]\log_3{(x+2)}-\log_3{(x-4)}=1\\ C.E.\: \left \{ {{x+2\ \textgreater \ 0} \atop {x-4\ \textgreater \ 0}} \right. \\ \log_3{\frac{x+2}{x-4}}=1\\ \frac{x+2}{x-4}=3^1\\ x+2=3(x-4)\\ x+2=3x-12\\ -2x=-14\\ x=7\:verifica\:C.E.[/tex]

Answer 2

Mult succes în continuare!