Question

$n=1+\frac{3}{2}+ \frac{5}{4}+ \frac{7}{6}+.....+ \frac{2011}{2010}-(1+\frac{1}{2} +\frac{1}{4} +\frac{1}{6} +....+ \frac{1}{2010})$

Answer 1

n=1+3/2+5/4+7/6+...+2011/2010-(1+1/2+1/4+1/6+...+1/2010)=
=1+3/2+5/4+7/6+...+2011/2010-1-1/2-1/4-1/6-...-1/2010=
=0+2/2+4/4+6/6+...+2010/2010=
=1+1+1+...+1=1×1005=1005
n termeni =(2010-2):2+1=1004+1=1005