Question

$numarul b= 1,25 : ( \frac{4}{5} ) ^{-2} + 1,(6) + 0,1(6)$ este:

Answer 1

1,25=1 intreg 25/100=1 intreg 1/4=5/4; 1,(6)=1 intreg 6/9=1 intreg 2/3 =5/3; 0,1(6)=(16-1)/90=15/90=1/6; 5/4*16/25+5/3+1,6=4/5+5/3+1/6 aducem la acelasi numitor =(24+50+5)/30=79/30