Question

$paranteza \: patrata( \frac{1}{2} ) {}^{3} - ( \frac{1}{6} ) {}^{3} in chidem \: paranteza \: patrata \times \frac{128 - 20 {}^{1} }{65 \div 5}$
Mulțumesc anticipat! ​

Answer 1

$[(\frac{1}{2})^{3} - (\frac{1}{6})^{3}]*\frac{128-20^{1} }{65:5} } =\\(\frac{1}{8}-\frac{1}{6^{3} } )*\frac{128-20}{13} =\\\frac{27}{26} -\frac{108}{13*6^{3} } =\\\frac{27}{26} -\frac{108}{13*216} =\\\frac{27}{26} - \frac{1}{13*2} =\\\frac{27}{26} -\frac{1}{26} =\\\frac{27-1}{26} = \frac{26}{26} = 1$