Question

$( \sqrt{2} + 3) {}^{3}$
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Answer 1

$\it (\sqrt2+3)^3=(\sqrt2)^3+3\cdot(\sqrt2)^2\cdot3+3\cdot\sqrt2\cdot3^2+3^3=2\sqrt2+18+27\sqrt2+27=\\ \\ \\ =45+29\sqrt2$

Answer 2

$( \sqrt{2} + 3) {}^{3} \\ formula \: (a + b) {}^{3} = a {}^{3} + 3a {}^{2}b + 3ab {}^{2} + b {}^{3}$

$= 2 \sqrt{2} + 18 + 27 \sqrt{2} + 27 = 29 \sqrt{2} + 18 + 27 = 29 \sqrt{2} + 45$